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Author Topic: Spherical Trigonometry Nathaniel posted July 21, 2015 11:28 AM                   Instead of using Pub. 249, I'm trying to get the Azimuth angle through spherical trig. But whenever I calculate I don't get the right results, can you see if I got the equation right. cos Z = cos(90-dec)-(cos(90-Ho)x cos(90-lat))/ (sin(90-Ho)x sin(90-lat)). From: Sweden David Burch posted July 21, 2015 11:30 AM                   We have the formulas in the glossary under navigation triangle http://www.starpath.com/cgi-bin/web_card/courses/glossary.pl?show_def=105&ca t=Celestial_Navigation There are several formulas that will get to the right result with special exceptions applied, but the ones we list are the best to use and should always work. From: Starpath, Seattle, WA Nathaniel posted July 21, 2015 11:47 AM                   Thanks David, just what I was looking for. From: Sweden

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