Author
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Topic: Lan examples in the test book
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Gerry
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posted September 21, 2008 08:36 AM
In example "A" noon sight page 3-15. I completed all the caculations and I can find all the information nesessary. I get the same lat of 43 deg 62.5' however I cannot determine how the answer 44 deg 2.5' N is derived.I have missed something somewhere.
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HHEW
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posted September 21, 2008 10:08 AM
Take a step back and look at the numbers. You have the correct answer: 62.5' are 1° 02.5', i.e. 43° 62.5' = 44° 02.5'.
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Gerry
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posted September 22, 2008 09:56 AM
Where did 1° 02.5' come from?
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Gerry
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posted September 22, 2008 10:00 AM
Disregard my last question! I just woke up.
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